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sIN 01-17-2009 01:14 PM

Math help
 
IS anyone here good at this stuff.

i have 3 questions to due. And was wondering if anyone could give me a hand.

1. A circle has x intercepts at A(1,0) and B(5,0) and its center lies on the line y = 4. Determine the equation of this circle?.

2. Find the points of intersection between the circle (x - 3)2+ (y-1)2 = 5 and the line y = 2x -2

3. Find the shortest distance between the point P(6,5) and the line 3x+4y=24.

any help would be awesome.

thank you.

Striker RS 01-17-2009 02:13 PM

i would say brown

mr_baboon 01-17-2009 02:43 PM

Quote:

Originally Posted by sIN (Post 6229560)
IS anyone here good at this stuff.

i have 3 questions to due. And was wondering if anyone could give me a hand.

1. A circle has x intercepts at A(1,0) and B(5,0) and its center lies on the line y = 4. Determine the equation of this circle?.

2. Find the points of intersection between the circle (x - 3)2+ (y-1)2 = 5 and the line y = 2x -2

3. Find the shortest distance between the point P(6,5) and the line 3x+4y=24.

any help would be awesome.

thank you.

Grade 12 stuff? I would do it for you if I had some paper in front of me. And it might involve some multi-variable vector calculus. But those questions are easy! C'mon now.

metal 01-17-2009 02:47 PM

6.2

Black SC2 01-17-2009 06:37 PM

Quote:

Originally Posted by mr_baboon (Post 6229699)
Grade 12 stuff? I would do it for you if I had some paper in front of me. And it might involve some multi-variable vector calculus. But those questions are easy! C'mon now.

Hey man, some of us had a hard time with Grade 12 Calc. It's not as hard as driving a MKIII Supra though, I hear that's really hard ;)

stevo911_ 01-17-2009 06:51 PM

i guess i shoudl probably brush up on that stuff for sept :\

WingHang 01-17-2009 07:59 PM

#1.

you know that the coordinate of the middle is (x,4)

(x - h)^2 + (y - k)^2 = r^2

in this equation you know that h and k is the coordinate of the midpoint of the circle..



(x - h)^2 + (y - 4)^2 = r^2

ok and you also know that on the circle exists coordinates (1,0)...and (5,0)
you need to plug in these 2 coordinates into the equation separately and you'll get 2 linear equatoins

(1 - h)^2 + (0 - 4)^2 = r^2
(5 - h)^2 + (0 - 4)^2 = r^2

subract these 2 equations from 1 another...

(1-h)^2 - (5-h)^2 = 0

(1-h)(1-h) - (5-h)(5-h) = 0

1-2h+h - (25-10h+h)=0

1-2h+h-25+10h-h=0

8h-24=0

h= 24/8 = 3

so u know the midpoint is (3,4)

ok so plug in this midpoint again back into your circle equation

(x - 3)^2 + (y - 4)^2 = r^2

and plug in (1,0) into this equation and solve for r.... (you can also plug in (5,0), or any other coordinate that exists on the circle)

(1 - 3)^2 + (0 - 4)^2 = r^2

4+16= r^2

r= sqrt(20)

final answer...
(x - 3)^2 + (y - 4)^2 = 20

sIN 01-17-2009 10:35 PM

thank you

Great68 01-18-2009 08:49 AM

You know,

After I graduated from post sec. I have never needed to find the equation of a circle who's center lies on the line y=4 and has intercepts of A(1,0) and B(5,0). It just hasn't come up.

Black SC2 01-18-2009 09:23 AM

Quote:

Originally Posted by Great68 (Post 6230786)
You know,

After I graduated from post sec. I have never needed to find the equation of a circle who's center lies on the line y=4 and has intercepts of A(1,0) and B(5,0). It just hasn't come up.

Maybe if you became a rocket surgeon?

shenmecar 01-18-2009 10:20 AM

must be calculating the radius of the cross section of a rocket........

ostampflee 01-18-2009 12:16 PM

Likewise... about the only post secondary math I've ever used is Discrete (binary, logic) and Newton's method.

Now, some of our programmers do lots of "fun" math all the time, but they're not in the department I run.

mr_baboon 01-18-2009 01:51 PM

Quote:

Originally Posted by Black SC2 (Post 6229999)
Hey man, some of us had a hard time with Grade 12 Calc. It's not as hard as driving a MKIII Supra though, I hear that's really hard ;)

Deep cut Christian :( But I guess I totally deserve it. Hahaha.

sIN 01-18-2009 04:33 PM

hey thanks for your help. it is greatly appreciated.

hud 91gt 01-18-2009 05:35 PM

I use simple trig all the time. But I wouldn't have a clue how to do this. Maybe if I really sat down and looked at it for an hour with paper and a calculator.

rental_metard 01-18-2009 06:27 PM

WingHang +1 respect

NashMan 01-18-2009 09:49 PM

mathamacation is the proper word for every thing when it comes to this type of stuff

laureate 01-18-2009 10:26 PM

lol couldn't find help in the Vancouver Board, had to come here? :haha:

sixthgear 01-19-2009 07:32 AM

Quote:

Originally Posted by laureate (Post 6232075)
lol couldn't find help in the Vancouver Board, had to come here? :haha:

Less chance someone here would rat on him for cheating?

As you may be able to tell, I am not a fan of someone posting their school work to get someone else to do it.

Black SC2 01-19-2009 05:16 PM

Quote:

Originally Posted by laureate (Post 6232075)
lol couldn't find help in the Vancouver Board, had to come here? :haha:

This thread was started before the one on the Van side.


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