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01-17-2009, 01:14 PM
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#1 | Need to Seek Professional Help
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IS anyone here good at this stuff.
i have 3 questions to due. And was wondering if anyone could give me a hand.
1. A circle has x intercepts at A(1,0) and B(5,0) and its center lies on the line y = 4. Determine the equation of this circle?.
2. Find the points of intersection between the circle (x - 3)2+ (y-1)2 = 5 and the line y = 2x -2
3. Find the shortest distance between the point P(6,5) and the line 3x+4y=24.
any help would be awesome.
thank you.
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01-17-2009, 02:13 PM
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#2 | My homepage has been set to RS
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i would say brown
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01-17-2009, 02:43 PM
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#3 | No Duplicate Accounts Allowed
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Originally Posted by sIN IS anyone here good at this stuff.
i have 3 questions to due. And was wondering if anyone could give me a hand.
1. A circle has x intercepts at A(1,0) and B(5,0) and its center lies on the line y = 4. Determine the equation of this circle?.
2. Find the points of intersection between the circle (x - 3)2+ (y-1)2 = 5 and the line y = 2x -2
3. Find the shortest distance between the point P(6,5) and the line 3x+4y=24.
any help would be awesome.
thank you. | Grade 12 stuff? I would do it for you if I had some paper in front of me. And it might involve some multi-variable vector calculus. But those questions are easy! C'mon now.
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01-17-2009, 02:47 PM
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#4 | OMGWTFBBQ is a common word I say everyday
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01-17-2009, 06:37 PM
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#5 | I answer every Emotion with an emoticon
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Originally Posted by mr_baboon Grade 12 stuff? I would do it for you if I had some paper in front of me. And it might involve some multi-variable vector calculus. But those questions are easy! C'mon now. | Hey man, some of us had a hard time with Grade 12 Calc. It's not as hard as driving a MKIII Supra though, I hear that's really hard
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01-17-2009, 06:51 PM
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#6 | B&S Sexy mod
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i guess i shoudl probably brush up on that stuff for sept |
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01-17-2009, 07:59 PM
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#7 | NOOB, Not Quite a Regular!
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#1.
you know that the coordinate of the middle is (x,4)
(x - h)^2 + (y - k)^2 = r^2
in this equation you know that h and k is the coordinate of the midpoint of the circle..
(x - h)^2 + (y - 4)^2 = r^2
ok and you also know that on the circle exists coordinates (1,0)...and (5,0)
you need to plug in these 2 coordinates into the equation separately and you'll get 2 linear equatoins
(1 - h)^2 + (0 - 4)^2 = r^2
(5 - h)^2 + (0 - 4)^2 = r^2
subract these 2 equations from 1 another...
(1-h)^2 - (5-h)^2 = 0
(1-h)(1-h) - (5-h)(5-h) = 0
1-2h+h - (25-10h+h)=0
1-2h+h-25+10h-h=0
8h-24=0
h= 24/8 = 3
so u know the midpoint is (3,4)
ok so plug in this midpoint again back into your circle equation
(x - 3)^2 + (y - 4)^2 = r^2
and plug in (1,0) into this equation and solve for r.... (you can also plug in (5,0), or any other coordinate that exists on the circle)
(1 - 3)^2 + (0 - 4)^2 = r^2
4+16= r^2
r= sqrt(20)
final answer...
(x - 3)^2 + (y - 4)^2 = 20
Last edited by WingHang; 01-17-2009 at 08:03 PM.
Reason: not quite done.
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01-17-2009, 10:35 PM
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#8 | Need to Seek Professional Help
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thank you
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01-18-2009, 08:49 AM
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#9 | Willing to sell body for a few minutes on RS
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You know,
After I graduated from post sec. I have never needed to find the equation of a circle who's center lies on the line y=4 and has intercepts of A(1,0) and B(5,0). It just hasn't come up.
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01-18-2009, 09:23 AM
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#10 | I answer every Emotion with an emoticon
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Originally Posted by Great68 You know,
After I graduated from post sec. I have never needed to find the equation of a circle who's center lies on the line y=4 and has intercepts of A(1,0) and B(5,0). It just hasn't come up. | Maybe if you became a rocket surgeon?
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01-18-2009, 10:20 AM
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#11 | RS.net, helping ugly ppl have sex since 2001
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must be calculating the radius of the cross section of a rocket........
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01-18-2009, 12:16 PM
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#12 | Even when im right, revscene.net is still right!
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Likewise... about the only post secondary math I've ever used is Discrete (binary, logic) and Newton's method.
Now, some of our programmers do lots of "fun" math all the time, but they're not in the department I run.
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01-18-2009, 01:51 PM
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#13 | No Duplicate Accounts Allowed
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Originally Posted by Black SC2 Hey man, some of us had a hard time with Grade 12 Calc. It's not as hard as driving a MKIII Supra though, I hear that's really hard  | Deep cut Christian  But I guess I totally deserve it. Hahaha.
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01-18-2009, 04:33 PM
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#14 | Need to Seek Professional Help
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hey thanks for your help. it is greatly appreciated.
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01-18-2009, 05:35 PM
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#15 | RS.net, helping ugly ppl have sex since 2001
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I use simple trig all the time. But I wouldn't have a clue how to do this. Maybe if I really sat down and looked at it for an hour with paper and a calculator.
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01-18-2009, 06:27 PM
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#16 | Sick motherfucker mod
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WingHang +1 respect
__________________ Quote: Originally posted by stevo911_ In this part of the world, the italian, the darkie, and the perv have total control.... scary eh? | |
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01-18-2009, 09:49 PM
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#17 | Willing to sell body for a few minutes on RS
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mathamacation is the proper word for every thing when it comes to this type of stuff
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01-18-2009, 10:26 PM
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#18 | Proud to be called a RS Regular!
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lol couldn't find help in the Vancouver Board, had to come here? |
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01-19-2009, 07:32 AM
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#19 | Rs has made me the man i am today!
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Originally Posted by laureate lol couldn't find help in the Vancouver Board, had to come here?  | Less chance someone here would rat on him for cheating?
As you may be able to tell, I am not a fan of someone posting their school work to get someone else to do it.
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Last edited by sixthgear; 01-19-2009 at 08:05 AM.
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01-19-2009, 05:16 PM
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#20 | I answer every Emotion with an emoticon
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Originally Posted by laureate lol couldn't find help in the Vancouver Board, had to come here?  | This thread was started before the one on the Van side.
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