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02-20-2012, 01:03 PM
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#1 | Even when im right, revscene.net is still right!
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| please help.... statistics
stuck on this question for 3 hours.... help please.. topic: distribution of the sample means
Tropicana orange juice buys all of its oranges from citrus orange grove in Florida. The amount of juice squeezed from each of these oranges is approximately normally distributed with a mean of 4.70 ounces and a standard deviation of 0.40 ounces.
Tangerine farms claims that only 4% of their oranges will contain less than 5 ounces of juice. tropicana decides to verify their claim by taking random sample of 500 oranges and counting how many contain less than 5 ounces of juice. 30 of the 500 oranges sampled contained less than 5 ounces. If tangerine's claim is true, that only 4% of their oranges contain less than 5 ounces of juice, what is the probability of getting 30 or more oranges containing less than 5 ounces in a sample of 500 oranges?
ANS: 0.0150 = 1.5%
i just pulled my last piece of hair out of my head... and still couldn't figure out answer...
BCIT business statistics ompt 1197
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02-20-2012, 01:19 PM
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#2 | SFICC-03*
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this is where you post your homework questions?
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02-20-2012, 01:22 PM
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#3 | OMGWTFBBQ is a common word I say everyday
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Lol stats, passed that last semester and glad i never have to look at it again.
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02-20-2012, 01:23 PM
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#4 | Even when im right, revscene.net is still right!
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i normally don't post my hws here, i'll figure out the answer most of the time... but i'm very very stuck on this one..
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02-20-2012, 01:28 PM
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#5 | I only answer to my username, my real name is Irrelevant!
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just take a break and go back to the question and separate it into categories
then take another break and come back to it hopefully it'll seem simple |
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02-20-2012, 02:04 PM
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#6 | RS.net, helping ugly ppl have sex since 2001
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don't you have friends in the class you can ask..?
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02-20-2012, 02:09 PM
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#7 | My homepage has been set to RS
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Any online statistics site related to your question in mind?
It's been a while and need a refresher to answer such question lol.
This question can't be worth much marks right?
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02-20-2012, 02:13 PM
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#8 | Even when im right, revscene.net is still right!
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| Quote:
Originally Posted by subordinate Any online statistics site related to your question in mind?
It's been a while and need a refresher to answer such question lol.
This question can't be worth much marks right? | does these help.??
z score = x-m/standard deviation
z score = standard / square root of N
and the normal distribution table..
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02-20-2012, 03:01 PM
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#9 | xxx
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Haven't done these types of stat problems in a while but here's the solution I came up with
Since 4% of oranges contain less than 5 oz of juice, and you have a sample of 500, it's pretty much binomial with n = 500, p = 0.04
so letting X = number of oranges having < 5oz of juice, X ~ Bin(500, 0.04)
so E(X) = 20
Var(X) = 19.2 and Standard deviation is sqrt(19.2)
You're asked to find Pr(X >= 30) (greater or equal to)
and since it's binomial which is discrete whereas normal is continuous you use the normal approximation and apply the continuity correction Pr(X >=30) = 1 - Pr (X < 30) = 1 - Pr ( X <=29) = 1 - Pr (X <= 29.5) because of the continuity correction.
So standardize this crap to get 1 - Pr (Z <= (29.5 - 20) / sqrt(19.2)) to get Z value of 2.17.
Then use this bad boy here:
to see that the cdf of Z-value 2.17 = 0.985
so 1 - 0.985 = 0.015
Last edited by Oleophobic; 02-20-2012 at 05:33 PM.
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02-20-2012, 03:21 PM
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#10 | :inoutugh:
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| Quote:
Originally Posted by Bahhbeehhaaaa ANS: 0.0150 = 1.5% | Quote:
Originally Posted by T.T so 1 - 0.985 = 0.015 | |
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02-20-2012, 03:23 PM
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#11 | RS.net, where our google ads make absolutely no sense!
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I think that's pretty much dead on...
Beginning of the question was totally unnecessary and didn't even make sense.. If the amount of juice is normally distributed with a mean of 4.7 ounces, how could the percentange of oranges with with <5 ounces be only 5%?
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02-20-2012, 05:26 PM
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#12 | The "You'd Know" Moderator
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^Tangerine farms are not part of the citrus orange grove in Florida. 
__________________ 08 CBR600RR 03 IS300 Ezekiel 25:17. The path of the righteous man is beset on all sides by the inequities of the selfish and the tyranny of evil men. Blessed is he who, in the name of charity and good will, shepherds the weak through the valley of the darkness. For he is truly his brother's keeper and the finder of lost children. And I will strike down upon thee with great vengeance and furious anger those who attempt to poison and destroy my brothers. And you will know I am the Lord when I lay my vengeance upon you. |
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02-20-2012, 06:54 PM
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#13 | I *heart* Revscene.net very Muchie
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I'd suggest you never take any stats courses beyond this.
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02-20-2012, 09:30 PM
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#14 | Rs has made me the man i am today!
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man... I'm looking at the solution and it's not ringing any bells~ All I remember from my 8am Stats 200 was that I either didn't wake up in time for it or that I ended up sleeping through it. In the end, they used some statistical standardization curve to allow me to pass |
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02-20-2012, 09:36 PM
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#15 | My name is PJ and I like dogs.
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Props to T.T
Maybe there should be a homework help section in RS
__________________ Studies show 100% of people die.. Might as well have some fun.
Hello my name is PJ. Buy/Sell Feedback 1-0-0 |
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02-20-2012, 09:59 PM
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#16 | Even when im right, revscene.net is still right!
Join Date: May 2011 Location: Van C
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| Quote:
Originally Posted by T.T Haven't done these types of stat problems in a while but here's the solution I came up with
Since 4% of oranges contain less than 5 oz of juice, and you have a sample of 500, it's pretty much binomial with n = 500, p = 0.04
so letting X = number of oranges having < 5oz of juice, X ~ Bin(500, 0.04)
so E(X) = 20
Var(X) = 19.2 and Standard deviation is sqrt(19.2)
You're asked to find Pr(X >= 30) (greater or equal to)
and since it's binomial which is discrete whereas normal is continuous you use the normal approximation and apply the continuity correction Pr(X >=30) = 1 - Pr (X < 30) = 1 - Pr ( X <=29) = 1 - Pr (X <= 29.5) because of the continuity correction.
So standardize this crap to get 1 - Pr (Z <= (29.5 - 20) / sqrt(19.2)) to get Z value of 2.17.
Then use this bad boy here:
to see that the cdf of Z-value 2.17 = 0.985
so 1 - 0.985 = 0.015  | THANKYOU SOOO MUCHHH!!! =) !!! stats is making my life miserable. Glade i'll be done in 3 weeks |
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02-20-2012, 10:04 PM
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#17 | Even when im right, revscene.net is still right!
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Originally Posted by flagella I'd suggest you never take any stats courses beyond this. | This is the only stats course i need lol
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02-20-2012, 10:15 PM
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#18 | DOES HE LOOK LIKE A BITCH?
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based on this thread, I've come up with the tentative solution that statistics is gay
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02-20-2012, 10:24 PM
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#19 | RS controls my life!
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Originally Posted by PJ Props to T.T
Maybe there should be a homework help section in RS  | ^ i concur
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02-20-2012, 10:26 PM
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#20 | I bringith the lowerballerith
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trust me .. better to draw out the normal distribution curve...that how I did those questions at BCIT stat. course
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02-20-2012, 10:47 PM
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#21 | Banned By Establishment
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| Quote:
Originally Posted by PJ Props to T.T
Maybe there should be a homework help section in RS  |
we do need one ! good idea! |
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02-20-2012, 11:01 PM
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#22 | xxx
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Originally Posted by Bahhbeehhaaaa THANKYOU SOOO MUCHHH!!! =) !!! stats is making my life miserable. Glade i'll be done in 3 weeks  |
lol np glad to help |
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02-20-2012, 11:05 PM
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#23 | :inoutugh:
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Originally Posted by Culture_Vulture based on this thread, I've come up with the tentative solution that statistics is gay | Please show your work.
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02-21-2012, 01:31 AM
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#24 | Banned (ABWS)?
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This is why I like RevScene. Probably more reliable than my classmates.
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02-21-2012, 02:29 AM
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#25 | Ask me about how I answered the question "How fat is TOO fat?"
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This just reminded me that I need to take Buec 333
fuuuuuuukk
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