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Probability Theory Question? is there a specific/academic terms or theory that explain this idea? Example: If you are to toss a coin 20 times, and all first 10 toss comes out as head, the probability of you getting a tail on your last 10 toss is still going to be 50/50. Just because you had heads on your previous toss will not make it more likely for you to get a tail on your next toss. *I am actually trying to explain this idea to a friend who believes there is a higher probability of winning on a slot machine that haven't had much winning before.... |
LOL... The more money you put into a slot machine the more likely it will pay you out |
Kinda apples to orange thing here. Your friend is right because slots are programmed to have a win every x amount of spins Posted via RS Mobile |
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so it is possible that 2 identical machine can have a vastly different payout even if they've been played the same amount of money/time |
i dont know anything about slot machines, but for your coin question...you're talking about "mutual exclusivity" and combinatorial probability. It basically says that if the two events (tossing a coin twice) cannot happen at the same time, then the two separate events should have no affect over one another. |
take him to the baccarat tables, the easy baccarat is 50/50 |
baccarat isnt really 50/50 because of commission.. slots are all pre-programmed so its not like flipping a coin, who knows what the programming is like inside |
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i.e. there is no such thing as "hot cycles", and a machine that just won the jackpot has the same probability of winning again on its next spin... |
then why is it that little old ladies scope out slot machines that people are not winning at to take over when they finally give up? |
Mutual exclusivity has nothing to do with this. Each toss is independent from each other, therefore the conditional probability of one more head given there has be X heads does not matter. i.e. the process is memoryless edit: However, slot machines is a completely different story, because we don't know that the events are independent. It depends on how the payouts were programmed. I think it's better if you use roulette or baccarat as an example. |
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Posted via RS Mobile |
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therefore even the best programming, cannot fail to take into account previous spins, wether they were 3 ago, or 300,000 ago If slots weren't programmed to work based on previous outcomes, even if that outcome only effects the next outcome by 0.1%, there would be alot more slot winners than there are. |
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Is your friend named diesel_test? |
independent events. each flip of the coin is independent of the next. The result of one flip has no bearing on the next flip |
slots are required by law to have a certain winning percentage, no? |
just tell your friend its elementary statistics Ask them: "50% chance x 1 flip = ??" If they say anything other than 50%, smack them in the head and repeat the process. The probability of them giving you the right answer after a few smacks should be quite good. Quote:
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ur friend noob gg |
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the probability of flipping a coin: P(heads) = 1/2 P(Tails) = 1/2 Sure the first few tosses might yield more heads than tails etc... but as time approaches inifnity the probabilities will also converge to 1/2 Things like flipping a coin is with replacement, so all flips are independent of each other. For stuff like slot machines. I was told that the older, non digital ones had a weigh scale inside - the more weight that was on the scale (from coins, tokens etc...), the higher the probability of a win With the new digital ones however, i doubt that is the case. Casinos are out to get your money, and are known to have less than ideal winning probabilities (in the perspective of the player) |
haha just bugging. i think what you wanna reference is something called binomial probability distribution or something.. btw: that chicken scratch is the heisenberg uncertainty principle. :troll: |
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